3/m+4-4/m=6m^2+25m+16+0

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Solution for 3/m+4-4/m=6m^2+25m+16+0 equation: 



3/m+4-4/m=6m^2+25m+16+0

We move all terms to the left:

3/m+4-4/m-(6m^2+25m+16+0)=0



Domain of the equation: m!=0

m∈R



We get rid of parentheses

-6m^2+3/m-4/m-25m-16-0+4=0

We multiply all the terms by the denominator


-6m^2*m-25m*m-16*m-0*m+4*m+3-4=0

We add all the numbers together, and all the variables

-6m^2*m-13m-25m*m-1=0

Wy multiply elements

-6m^3-25m^2-13m-1=0

We do not support empression: m^3

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